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			<title>4ch4n - phys3</title>
			<link>http://4ch4n.org/phys3</link>
			<description>Live RSS feed for http://4ch4n.org/phys3</description>
			<language>en</language><item>
				<title>64</title>
				<link>http://4ch4n.org/phys3/res/53.html#64</link><description><![CDATA[Introduction to Electric Current<br><br>Part A: Copper, Aluminum, Gold<br><br>Part B: They possess high concentrations of free electrons<br><br>Part C: 10^-4<br><br>Part D: square the radius, and multiply by drift speed<br><br>Part E: the internal electric field in the wire<br><br>Part F: nonuniform<br><br>]]></description>
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				<title>63</title>
				<link>http://4ch4n.org/phys3/res/53.html#63</link><description><![CDATA[A) Copper, aluminum, and gold<br>B) high concentrations of free electrons<br>C) 10^-4<br>D) from most current to least current in terms of radius:<br>2r, 3r, 4r, 1r.<br>E) internal electric field<br>F) nonuniform<br><br>]]></description>
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				<title>62</title>
				<link>http://4ch4n.org/phys3/res/53.html#62</link><description><![CDATA[HAHAHAHHA ROGER FREEDMAN YOU CRACK MY ASS UP HOLY SHIT<br><br>]]></description>
				</item><item>
				<title>61</title>
				<link>http://4ch4n.org/phys3/res/53.html#61</link><description><![CDATA[A)  (I)/(cross section in meters)^2<br>B)(1.72*10^-8)(answer from part A)<br>C)(Length)/[(answer to part A)/(1.36*10^10)]<br><br>]]></description>
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				<title>60</title>
				<link>http://4ch4n.org/phys3/res/53.html#60</link><description><![CDATA[you guys are lifesavers....im BLACKED OUT right now boozin hard<br><br>]]></description>
				</item><item>
				<title>59</title>
				<link>http://4ch4n.org/phys3/res/53.html#59</link><description><![CDATA[Here you go peeps<br><br>A) Large pipe<br>B) The sum of the flows<br>C) drop is the same<br>D) flow through each segment is same as overall flow, the sum of the changes in pressure in each segment equals the overall change<br><br>]]></description>
				</item><item>
				<title>58</title>
				<link>http://4ch4n.org/phys3/res/53.html#58</link><description><![CDATA[i dont know where it went but:<br><br>25.2<br><br>a.) 8.8*10^-2<br>b.) 1.8*10^-6<br><br>]]></description>
				</item><item>
				<title>57</title>
				<link>http://4ch4n.org/phys3/res/53.html#57</link><description><![CDATA[A)E<br>B)Not enough info<br>C)D<br>D)Not enough info<br>E)Not enough info<br>F)C<br>G)B<br>H)2<br>I)2<br><br>]]></description>
				</item><item>
				<title>56</title>
				<link>http://4ch4n.org/phys3/res/53.html#56</link><description><![CDATA[25.12 arent right : (<br><br>]]></description>
				</item><item>
				<title>55</title>
				<link>http://4ch4n.org/phys3/res/53.html#55</link><description><![CDATA[Part a) 6.6 * 10^5<br>Part b) 1.1 * 10^-2<br>Part c) 7.4 * 10^4<br><br>Someone else, the rest please!!!<br><br>]]></description>
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				<title>54</title>
				<link>http://4ch4n.org/phys3/res/53.html#54</link><description><![CDATA[Part A)<br>I = Q/T<br>I = 8.8*10^-2<br><br>Part B)<br>v = I/(nqA)<br>v = 1.8*10^-6<br><br>Anyone have the rest?<br><br>]]></description>
				</item><item>
				<title>53</title>
				<link>http://4ch4n.org/phys3/res/53.html</link><description><![CDATA[[http://4ch4n.org/phys3/src/122731096143.jpg] <br /><br>Assignment 8 anyone?<br><br>]]></description>
				</item><item>
				<title>52</title>
				<link>http://4ch4n.org/phys3/res/47.html#52</link><description><![CDATA[thanks guys!<br><br>]]></description>
				</item><item>
				<title>51</title>
				<link>http://4ch4n.org/phys3/res/47.html#51</link><description><![CDATA[Part A:<br>Charge on C1 divided by capacitance of C1.<br><br>Part B:<br>Voltage from a to b minus the answer from part A.<br><br>Cheers!<br><br>]]></description>
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				<title>50</title>
				<link>http://4ch4n.org/phys3/res/47.html#50</link><description><![CDATA[thanks! does anyone know 24.19?<br><br>]]></description>
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